b^2-5/3b=0

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Solution for b^2-5/3b=0 equation: 


b in (-oo:+oo)

b^2-((5/3)*b) = 0

b^2+(-5/3)*b = 0

b^2-5/3*b = 0

DELTA = (-5/3)^2-(0*1*4)

DELTA = 25/9

DELTA > 0

b = ((25/9)^(1/2)+5/3)/(1*2) or b = (5/3-(25/9)^(1/2))/(1*2)

b = 5/3 or b = 0

b in { 0, 5/3 }

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